2003 AMC 10B Problem 1 — Solution | LIVE by Po-Shen Loh

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2003 AMC 10B Problem 1

Attempt Problem 1 of the 2003 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Which of the following is the same as

$\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}?$

$-1$

$-\dfrac{2}{3}$

$\dfrac{2}{3}$

$1$

$\dfrac{14}{3}$

Answer: C

Concepts:fraction distributive property

Difficulty rating: 660

Solution:

Factoring gives $\dfrac{2(1-2+3-4+5-6+7)}{3(1-2+3-4+5-6+7)}.$ The identical alternating sums cancel, leaving $\dfrac{2}{3}.$

Thus, the correct answer is C.

Problem 2#2 →

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