2003 AMC 10A Problem 1

Attempt Problem 1 of the 2003 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

What is the difference between the sum of the first 20032003 even counting numbers and the sum of the first 20032003 odd counting numbers?
00
11
22
20032003
40064006
Answer: D
Concepts:summationpairing and grouping
Small hint:
Pair each even number with the odd number just below it
Big hint:
Each of the 20032003 pairs contributes a difference of 11
Solution:
The kkth even number 2k2k is exactly 11 more than the kkth odd number 2k−1.2k-1.
Summing this difference over all 20032003 pairs gives 2003⋅1=2003.2003 \cdot 1 = 2003.
Thus, the correct answer is D.
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