2001 AMC 10 Problem 11

Attempt Problem 11 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

Consider the dark square in an array of unit squares, part of which is shown. The first ring of squares around this center square contains 88 unit squares. The second ring contains 1616 unit squares. If we continue this process, the number of unit squares in the 100100th ring is
396396
404404
800800
10,00010{,}000
10,40410{,}404
Answer: C
Concepts:difference of squarespattern recognition
Small hint:
The nnth ring is a (2n+1)×(2n+1)(2n+1)\times(2n+1) square with the (2n−1)×(2n−1)(2n-1)\times(2n-1) square removed
Big hint:
(2n+1)2−(2n−1)2=8n(2n+1)^2-(2n-1)^2=8n
Solution:
The nnth ring is the border of a (2n+1)×(2n+1)(2n+1)\times(2n+1) square surrounding a (2n−1)×(2n−1)(2n-1)\times(2n-1) square, so it contains (2n+1)2−(2n−1)2=8n(2n+1)^2-(2n-1)^2=8n unit squares.
For n=100,n=100, that is 800.800. Thus, the correct answer is C.
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