2010 AIME II Problem 11

Below is the professionally curated solution for Problem 11 of the 2010 AIME II, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AIME II solutions, or check the answer key.

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Concepts:complementary countingcasework

Difficulty rating: 3060

11.

Define a T-grid to be a 3×33 \times 3 matrix which satisfies the following two properties: (1) exactly five of the entries are 11's, and the remaining four entries are 00's, and (2) among the eight rows, columns, and long diagonals (the long diagonals are {a13,a22,a31}\{a_{13}, a_{22}, a_{31}\} and {a11,a22,a33}\{a_{11}, a_{22}, a_{33}\}), no more than one of the eight has all three entries equal. Find the number of distinct T-grids.

Solution:

There are (95)=126\binom{9}{5} = 126 matrices satisfying (1); we subtract those with two or more constant lines. Two lines of 00's are impossible (they would need at least 55 zeros), and a line of 11's and a line of 00's cannot cross, so they must be parallel rows or parallel columns; likewise two lines of 11's cannot be parallel (66 ones), so they must cross, using exactly 3+31=53 + 3 - 1 = 5 ones.

Case 1: a line of 11's and a parallel line of 00's. There are 66 choices for the all-11 row or column, 22 for the parallel all-00 line, and 33 ways to fill the remaining parallel line with two 11's and one 0:0: 623=366 \cdot 2 \cdot 3 = 36 matrices. Every perpendicular line then contains both a 11 and a 0,0, so no third constant line appears and nothing is double-counted.

Case 2: two crossing lines of 11's and 00's elsewhere. The pair can be a row and a column (33=93 \cdot 3 = 9), a row or column with a diagonal (62=126 \cdot 2 = 12), or the two diagonals (11), for 2222 matrices; one checks the four remaining 00's never form a constant line. So 1263622=68.126 - 36 - 22 = 68.

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