2010 AIME I Problem 3

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3.

Suppose that y=34xy = \frac{3}{4}x and xy=yx.x^y = y^x. The quantity x+yx + y can be expressed as a rational number rs,\frac{r}{s}, where rr and ss are relatively prime positive integers. Find r+s.r + s.

Answer: 529
Concepts:exponentsubstitution
Difficulty rating: 2230
Solution:

Substituting y=34xy = \frac{3}{4}x into xy=yxx^y = y^x gives x34x=(34x)x.x^{\frac{3}{4}x} = \left(\tfrac{3}{4}x\right)^{x}. Taking xxth roots (the quantities here are positive), x3/4=34x,x^{3/4} = \frac{3}{4}x, so dividing by xx yields x1/4=34,x^{-1/4} = \frac{3}{4}, that is, x=(43)4=25681.x = \left(\frac{4}{3}\right)^4 = \frac{256}{81}.

Then y=3425681=6427,y = \frac{3}{4} \cdot \frac{256}{81} = \frac{64}{27}, and x+y=25681+19281=44881.x + y = \frac{256}{81} + \frac{192}{81} = \frac{448}{81}. Since gcd(448,81)=1,\gcd(448, 81) = 1, the answer is 448+81=529.448 + 81 = 529.

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