1992 AIME Problem 3

Attempt Problem 3 of the 1992 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AIME solutions, or check the answer key.

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3.

A tennis player computes her win ratio by dividing the number of matches she has won by the total number of matches she has played. At the start of a weekend, her win ratio is exactly 0.500.0.500. During the weekend, she plays four matches, winning three and losing one. At the end of the weekend, her win ratio is greater than 0.503.0.503. What’s the largest number of matches she could’ve won before the weekend began?

Answer: 164
Concepts:ratio and proportioninequalitypercentage
Difficulty rating: 1640
Small Hint:

If she had ww wins initially, a 0.5000.500 ratio means she had played 2w2w matches

Big Hint:

Translate the final ratio into a strict inequality before taking the largest integer ww

Solution:

If she initially had ww wins, then she had played 2w2w matches. The final condition is w+32w+4>5031000.\frac{w+3}{2w+4}\gt\frac{503}{1000}. Cross-multiplication gives 1000w+3000>1006w+2012,1000w+3000\gt1006w+2012, so 6w<9886w\lt988 and w<16423.w\lt164\frac23. The largest possible integer is 164.164.

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