2008 AIME I Problem 3

Attempt Problem 3 of the 2008 AIME I below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AIME I solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Ed and Sue bike at equal and constant rates. Similarly, they jog at equal and constant rates, and they swim at equal and constant rates. Ed covers 7474 kilometers after biking for 22 hours, jogging for 33 hours, and swimming for 44 hours, while Sue covers 9191 kilometers after jogging for 22 hours, swimming for 33 hours, and biking for 44 hours. Their biking, jogging, and swimming rates are all whole numbers of kilometers per hour. Find the sum of the squares of Ed’s biking, jogging, and swimming rates.
Answer: 314
Concepts:system of equationsDiophantine Equationrate
Small hint:
The two trips give 2b+3j+4s=742b + 3j + 4s = 74 and 4b+2j+3s=914b + 2j + 3s = 91 in whole numbers
Big hint:
Eliminate bb to get 4j+5s=57;4j + 5s = 57; of its three positive solutions, only one makes bb a whole number
Solution:
Let b,b, j,j, and ss be the biking, jogging, and swimming rates. The two trips give 2b+3j+4s=742b + 3j + 4s = 74 and 4b+2j+3s=91.4b + 2j + 3s = 91. Doubling the first equation and subtracting the second yields 4j+5s=57,4j + 5s = 57, whose positive integer solutions are (j,s)=(13,1),(j, s) = (13, 1), (8,5),(8, 5), and (3,9).(3, 9).
The corresponding values of 2b=74−3j−4s2b = 74 - 3j - 4s are 31,31, 30,30, and 29,29, so only (j,s)=(8,5)(j, s) = (8, 5) gives a whole-number rate, b=15.b = 15. The sum of the squares is 152+82+5215^2 + 8^2 + 5^2 =225+64+25= 225 + 64 + 25 =314.= 314.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.