2007 AIME I Problem 3

Attempt Problem 3 of the 2007 AIME I below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AIME I solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The complex number zz is equal to 9+bi,9 + bi, where bb is a positive real number and i2=−1.i^2 = -1. Given that the imaginary parts of z2z^2 and z3z^3 are equal, find b.b.
Answer: 15
Concepts:complex numberbinomial theorem
Small hint:
Expand (9+bi)2(9 + bi)^2 and (9+bi)3(9 + bi)^3 with the binomial theorem and extract the imaginary parts
Big hint:
Both imaginary parts are divisible by b;b; cancel it before solving
Solution:
By the binomial theorem, z2=(81−b2)+18biz^2 = (81 - b^2) + 18bi and z3=(729−27b2)z^3 = (729 - 27b^2) +(243b−b3)i.+ (243b - b^3)i. Setting the imaginary parts equal gives 18b=243b−b3.18b = 243b - b^3.
Since bb is positive we may divide by b,b, leaving b2=243−18=225,b^2 = 243 - 18 = 225, so b=15.b = 15.
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