2003 AIME II Problem 4

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4.

In a regular tetrahedron, the centers of the four faces are the vertices of a smaller tetrahedron. The ratio of the volume of the smaller tetrahedron to that of the larger is mn,\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+n.m + n.

Answer: 28
Concepts:homothetycentroidpower scaling of length, area, and volume
Difficulty rating: 2180
Solution:

Use position vectors, and let G=A+B+C+D4G = \frac{A + B + C + D}{4} be the centroid of the tetrahedron. The center of the face opposite AA is B+C+D3=4GA3=G13(AG), \begin{aligned} \frac{B + C + D}{3} &= \frac{4G - A}{3} \\ &= G - \frac{1}{3}(A - G), \end{aligned} so each face center is the image of the opposite vertex under the homothety centered at GG with ratio 13.-\frac{1}{3}.

Hence the smaller tetrahedron is similar to the larger with ratio 13,\frac{1}{3}, and its volume is (13)3=127\left(\frac{1}{3}\right)^3 = \frac{1}{27} of the larger. Thus m+n=1+27=28.m + n = 1 + 27 = 28.

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