2002 AIME II Problem 4

Below is the professionally curated solution for Problem 4 of the 2002 AIME II, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AIME II solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:regular polygonsummationarea decomposition

Difficulty rating: 2340

4.

Patio blocks that are regular hexagons 11 unit on a side are used to outline a garden by placing the blocks edge to edge with nn on each side. The diagram indicates the path of blocks around the garden when n=5.n = 5.

If n=202,n = 202, then the area of the garden enclosed by the path, not including the path itself, is m(3/2)m\left(\sqrt{3}/2\right) square units, where mm is a positive integer. Find the remainder when mm is divided by 1000.1000.

Solution:

The garden enclosed by the path is itself a hexagonal arrangement of unit hexagons with n1n - 1 on each side. Counting from the center outward in rings of 6,12,6, 12, \ldots hexagons, it contains 1+6+12++6(n2)=1+3(n2)(n1)1 + 6 + 12 + \cdots + 6(n-2) = 1 + 3(n-2)(n-1) blocks, which for n=202n = 202 is 1+3200201=120601.1 + 3 \cdot 200 \cdot 201 = 120601.

Each unit hexagon consists of 66 equilateral triangles of side 1,1, so its area is 634=332.6 \cdot \frac{\sqrt{3}}{4} = 3 \cdot \frac{\sqrt{3}}{2}. The garden's area is therefore 3120601=3618033 \cdot 120601 = 361803 times 32,\frac{\sqrt{3}}{2}, so m=361803,m = 361803, and the remainder upon division by 10001000 is 803.803.

← Problem 3Full ExamProblem 5

Problem 4 in Other Years