1985 AIME Problem 4

Attempt Problem 4 of the 1985 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1985 AIME solutions, or check the answer key.

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4.

A small square is constructed inside a square of area 11 by dividing each side of the unit square into nn equal parts, and then connecting the vertices to the division points closest to the opposite vertices, as shown. Find the value of nn if the area of the small square (shaded in the figure) is exactly 11985.\frac1{1985}.

Answer: 32
Concepts:square (geometry)distance formulaquadratic
Difficulty rating: 2260
Small Hint:

Place the unit square on a coordinate plane and write equations for two parallel construction lines

Big Hint:

The distance between the parallel lines is the side length of the small square

Solution:

Put the outer square at (0,0),(0,0), (1,0),(1,0), (1,1),(1,1), (0,1).(0,1). One pair of construction lines has equations nx(n1)y=0,nx(n1)y=1. \begin{aligned} nx-(n-1)y&=0,\\ nx-(n-1)y&=1. \end{aligned} The other pair is perpendicular to this pair, and the two pairs have the same separation. Thus the inner square has side length 1n2+(n1)2 \frac1{\sqrt{n^2+(n-1)^2}} and area 1n2+(n1)2.\frac{1}{n^2+(n-1)^2}. Hence n2+(n1)2=1985, n^2+(n-1)^2=1985, or n2n992=0.n^2-n-992=0. Its positive root is n=1+632=32.n=\frac{1+63}{2}=32.

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