Answer: 432

Small Hint:

Separate the case where the repeated digit is $1$ from the case where it is not

Big Hint:

In each case, choose the repeated digit’s positions before choosing the remaining distinct digit

Solution:

If $1$ is the repeated digit, exactly one of the last three positions contains $1.$ There are $3$ choices for that position, $9$ choices for the next digit, and $8$ for the last digit, since those two digits must differ from each other and from $1.$ This gives $3\cdot9\cdot8=216$ numbers.

If a digit other than $1$ is repeated, there are $9$ choices for that digit, $3$ ways to choose its two positions among the last three, and $8$ choices for the remaining digit. This gives another $9\cdot3\cdot8=216$ numbers. The total is $216+216=432.$