1986 AIME Problem 10

Attempt Problem 10 of the 1986 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AIME solutions, or check the answer key.

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10.

In a parlor game, the magician asks one of the participants to think of a three-digit number (abc),(abc), where a,a, b,b, and cc represent base-1010 digits in the indicated order. The magician then asks this person to form the numbers (acb),(acb), (bca),(bca), (bac),(bac), (cab),(cab), and (cba),(cba), to add these five numbers, and to reveal their sum N.N. If told N,N, the magician can identify the original number (abc).(abc). Play the role of the magician and determine (abc)(abc) if N=3194.N=3194.

Answer: 358
Concepts:digitsplace valuesystem of equations
Difficulty rating: 1830
Small Hint:

First include the original number and sum all six permutations

Big Hint:

If s=a+b+c,s=a+b+c, express the original number in terms of ss and NN

Solution:

Across all six permutations, each digit occurs twice in each place, so their total is 222(a+b+c).222(a+b+c). Put s=a+b+cs=a+b+c and let the original number be M.M. Since the other five sum to 3194,3194, M=222s3194. M=222s-3194. Because 100M999,100\leq M\leq999, we need 15s18.15\leq s\leq18. Testing these four values gives M=136,M=136, M=358,M=358, M=580,M=580, and M=802,M=802, respectively. Only 358358 has digit sum equal to its assumed value, namely 16.16. Therefore the original number is 358.358.

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