2014 AMC 8 第 15 题

先试着解答 2014 AMC 8 第 15 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2014 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

圆心为 OO 的圆周被分成 1212 段相等的弧,并如图标上字母 AA 到 LL。角 xx 与 yy 的和是多少度?
The circumference of the circle with center OO is divided into 1212 equal arcs, marked the letters AA through LL as seen below. What is the number of degrees in the sum of the angles xx and y?y?
75 75
80 80
90 90
120 120
150 150
答案:C
知识点:弧等腰三角形导角
小提示:
相邻两个字母在圆心处截出的角为 30∘30^\circ
Each adjacent pair of letters cuts off 30∘30^\circ at the center.
大提示:
两个相关三角形都是等腰三角形,因为它们的边是半径
The two relevant triangles are isosceles because their sides are radii.
解答:
1212 段弧等分圆周,所以每段弧对应的圆心角为 360∘12=30∘\frac{360^{\circ}}{12} = 30^{\circ}。
∠AOE\angle AOE 跨过 44 段弧,所以 ∠AOE=4⋅30∘=120∘。\angle AOE = 4 \cdot 30^{\circ} = 120^{\circ}\text{。}类似地,∠GOI=2⋅30∘=60∘。\angle GOI = 2 \cdot 30^{\circ} = 60^{\circ}\text{。}我们还知道这两个三角形都是等腰三角形,因为它们各有两条边是半径。因此 x=180−1202=30∘ x = \dfrac{180 - 120}{2} = 30^{\circ} 且 y=180−602=60∘。 y = \dfrac{180 - 60}{2} = 60^{\circ}\text{。}所以 x+y=90∘x + y = 90^{\circ}。
所以正确答案是 C。
Note that each of the 1212 arcs splits the circle evenly, so they each cover 360∘12=30∘.\frac{360^{\circ}}{12} = 30^{\circ}.
∠AOE\angle AOE spans 44 of these arcs, so ∠AOE=4⋅30∘=120∘.\angle AOE = 4 \cdot 30^{\circ} = 120^{\circ}. Similarly, ∠GOI=2⋅30∘=60∘.\angle GOI = 2 \cdot 30^{\circ} = 60^{\circ}. We also know that both triangles are isosceles since two of their sides are radii. Therefore, x=180−1202=30∘ x = \dfrac{180 - 120}{2} = 30^{\circ} and y=180−602=60∘. y = \dfrac{180 - 60}{2} = 60^{\circ}. Therefore, x+y=90∘.x + y = 90^{\circ}.
Thus, C is the correct answer.
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