2014 AMC 8 第 15 题

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15.

圆心为 OO 的圆周被分成 1212 段相等的弧,并如图标上字母 AALL。角 xxyy 的和是多少度?

The circumference of the circle with center OO is divided into 1212 equal arcs, marked the letters AA through LL as seen below. What is the number of degrees in the sum of the angles xx and y?y?

75 75

80 80

90 90

120 120

150 150

答案:C
知识点:等腰三角形导角
难度评级:1220
解答:

1212 段弧等分圆周,所以每段弧对应的圆心角为 360/12=30360^{\circ} / 12 = 30^{\circ}

AOE\angle AOE 跨过 44 段弧,所以 AOE=430=120.\angle AOE = 4 \cdot 30^{\circ} = 120^{\circ}. 类似地,GOI=230=60.\angle GOI = 2 \cdot 30^{\circ} = 60^{\circ}. 两个三角形都是等腰三角形,因此 x=1801202=30 x = \dfrac{180 - 120}{2} = 30^{\circ} y=180602=60. y = \dfrac{180 - 60}{2} = 60^{\circ}. 所以 x+y=90x + y = 90^{\circ}

所以正确答案是 C

Note that each of the 1212 arcs splits the circle evenly, so they each cover 360/12=30.360^{\circ} / 12 = 30^{\circ}.

AOE\angle AOE spans 44 of these arcs, so AOE=430=120.\angle AOE = 4 \cdot 30^{\circ} = 120^{\circ}. Similarly, GOI=230=60.\angle GOI = 2 \cdot 30^{\circ} = 60^{\circ}. We also know that both triangles are isosceles since two of their sides are radii. Therefore, x=1801202=30 x = \dfrac{180 - 120}{2} = 30^{\circ} and y=180602=60. y = \dfrac{180 - 60}{2} = 60^{\circ}. Therefore, x+y=90.x + y = 90^{\circ}.

Thus, C is the correct answer.

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