2010 AMC 8 第 15 题

先试着解答 2010 AMC 8 第 15 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

一个罐子里有 55 种不同颜色的软糖。30%30\% 是蓝色,20%20\% 是棕色,15%15\% 是红色,10%10\% 是黄色,另外 3030 颗是绿色。如果把一半蓝色软糖换成棕色软糖,那么会有多少颗棕色软糖?
A jar contains 55 different colors of gum drops. 30%30\% are blue, 20%20\% are brown, 15%15\% are red, 10%10\% are yellow, and the other 3030 gum drops are green. If half of the blue gum drops are replaced by brown gum drops, how many gum drops will be brown?
 35\ 35
 36\ 36
 42\ 42
 48\ 48
 64\ 64
答案:C
知识点:百分数
小提示:
用绿色软糖数量求总数,再把一半蓝色数量转到棕色
Use the green count to find the total, then move half the blue count to brown.
大提示:
先求罐子中绿色软糖占百分之多少
Find what percent of the jar is green.
解答:
绿色所占百分比是 100%100\% 减去其他颜色百分比之和:100%−30%−20%−100\%-30\%-20\%- 15%−10%=25%15\%-10\% = 25\%
因为 3030 颗绿色软糖是总数的 25%25\%,所以软糖总数为 300.25=120\dfrac { 30}{0.25} = 120。
一开始棕色软糖有 0.2⋅120=240.2\cdot120 = 24 颗,蓝色软糖有 0.3⋅120=360.3\cdot120 = 36 颗。把一半蓝色换成棕色会增加 362=18\dfrac{36}{2} = 18 颗棕色软糖。因此棕色软糖共有 24+18=4224+18= 42 颗。
所以正确答案是 C。
Since we have percentages for every color except green, the percent of green is 100%100\% minus the sum of the other colors. This would make the percent of green equal to 100%−30%−20%−100\%-30\%-20\%-15%−10%=25%15\%-10\% = 25\%
Since we know 3030 gum drops is 25%,25\%, we know that the total number of gum drops is 300.25=120.\dfrac { 30}{0.25} = 120.
This means there are 0.2⋅120=240.2\cdot120 = 24 brown gum drops to start and 0.3⋅120=360.3\cdot120 = 36 blue gum drops. If half of the blue gum drops are turned to brown, then 362=18 \dfrac{36}{2} = 18 more brown gum drops are added. Therefore, we have 24+18=4224+18= 42 brown gum drops.
Thus, the answer is C .
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.