2007 AMC 8 第 20 题

先试着解答 2007 AMC 8 第 20 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2007 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

20.

在分区赛前,Unicorns 赢了他们篮球比赛的 45%45 \%。分区赛中,他们又赢六场、输两场,最终以胜率一半结束赛季。Unicorns 总共打了多少场比赛?
Before district play, the Unicorns had won 45%45 \% of their basketball games. During district play, they won six more games and lost two, to finish the season having won half their games. How many games did the Unicorns play in all?
4848
5050
5252
5454
6060
答案:A
知识点:一次方程百分数
小提示:
设 xx 为分区赛前的比赛数
Let xx be the number of games before district play.
大提示:
写出分区赛后总胜场等于总比赛数一半的方程
Write an equation comparing total wins after district play with half of all games played.
解答:
设 Unicorns 分区赛前打了 xx 场比赛。那么分区赛前赢了 0.45x0.45x 场,分区赛后共赢了 0.45x+60.45x+6 场。
他们总共打了 x+8x+8 场。题意给出 0.45x+6=x+82。0.45x+6=\dfrac{x+8}{2}\text{。}
解得 0.45x+6=0.5x+40.45x+6=0.5x+4,所以 2=0.05x2=0.05x,x=40x=40。因此 Unicorns 总共打了 40+8=4840+8=48 场。
所以正确答案是 A。
Let xx be the number of games the Unicorns had played before district play. Then they had won 0.45x0.45x games before district play and 0.45x+60.45x+6 games after district play.
In total, they played x+8x+8 games. The problem statement tells us that 0.45x+6=x+82.0.45x+6=\dfrac{x+8}{2}.
Solving gives 0.45x+6=0.5x+40.45x+6=0.5x+4, so 2=0.05x2=0.05x, and x=40x=40. Therefore, the Unicorns played 40+8=4840+8=48 games in all.
Thus, A is the correct answer.
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