2004 AMC 8 第 15 题

先试着解答 2004 AMC 8 第 15 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2004 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

十三块阴影六边形瓷砖和六块未阴影六边形瓷砖组成下图。如果用与其他瓷砖大小和形状相同的未阴影瓷砖加上一圈边框形成新图形,新图形中未阴影瓷砖总数与阴影瓷砖总数之差是多少?
Thirteen shaded and six unshaded hexagonal tiles were used to create the figure below. If a new figure is created by attaching a border of unshaded tiles with the same size and shape as the others, what will be the difference between the total number of unshaded tiles and the total number of shaded tiles in the new figure?
55
77
1111
1212
1818
答案:C
知识点:铺砖找规律
小提示:
原图有一个中心瓷砖、一圈 66 块和一圈 1212 块
The original figure has one center tile, a ring of 6,6, and a ring of 12.12.
大提示:
下一圈六边形边框有 1818 块瓷砖
The next hexagonal border has 1818 tiles.
解答:
原图有 1313 块阴影瓷砖和 66 块未阴影瓷砖。
新边框是围绕图形的下一圈六边形环,有 1818 块未阴影瓷砖。
新图形有 6+18=246+18=24 块未阴影瓷砖和 1313 块阴影瓷砖,所以差为 24−13=1124-13=11。
所以正确答案是 C。
The original figure has 1313 shaded tiles and 66 unshaded tiles.
The new border is the next hexagonal ring around the figure, which has 1818 unshaded tiles.
The new figure has 6+18=246+18=24 unshaded tiles and 1313 shaded tiles, so the difference is 24−13=11.24-13=11.
Thus, C is the correct answer.
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