1996 AMC 8 第 23 题

先试着解答 1996 AMC 8 第 23 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1996 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

一家公司经理原计划从公司基金中给每位员工发 $50\$50 奖金,但基金比所需金额少 $5\$5。于是经理改为给每位员工发 $45\$45 奖金,并在公司基金中留下 $95\$95。发放任何奖金之前,公司基金中有多少钱?
The manager of a company planned to distribute a $50\$50 bonus to each employee from the company fund, but the fund contained $5\$5 less than what was needed. Instead the manager gave each employee a $45\$45 bonus and kept the remaining $95\$95 in the company fund. The amount of money in the company fund before any bonuses were paid was
$945\$945
$950\$950
$955\$955
$990\$990
$995\$995
答案:E
知识点:一次方程
小提示:
设员工人数为 nn;基金数等于 50n−550n - 5,也等于 45n+9545n + 95。
Let nn be the number of employees; the fund equals 50n−550n - 5 and also 45n+9545n + 95
大提示:
令两个基金表达式相等,解出 nn,再计算基金数。
Set the two expressions for the fund equal to solve for n,n, then compute the fund
解答:
设员工人数为 nn。基金数为 50n−550n - 5(比每人 5050 美元少五美元),也等于 45n+9545n + 95。
令 50n−5=45n+9550n - 5 = 45n + 95,得 5n=1005n = 100,所以 n=20n = 20。基金数为 45⋅20+95=99545 \cdot 20 + 95 = 995 美元。
所以正确答案是 E。
Let nn be the number of employees. The fund is 50n−550n - 5 (five dollars short of 5050 each) and also 45n+95.45n + 95.
Setting 50n−5=45n+9550n - 5 = 45n + 95 gives 5n=100,5n = 100, so n=20.n = 20. The fund is 45⋅20+95=995.45 \cdot 20 + 95 = 995.
Thus, the correct answer is E .
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