2012 AMC 8 Problem 23

Below is the video solution and professionally curated solution for Problem 23 of the 2012 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.

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Concepts:equilateral triangleregular polygonarea ratio

Difficulty rating: 1540

23.

An equilateral triangle and a regular hexagon have equal perimeters. If the triangle's area is 44, what is the area of the hexagon?

4 4

5 5

6 6

43 4\sqrt3

63 6\sqrt3

Video solution:
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Written solution:

Let the side length of the triangle be s.s. This means the perimeter is 3s.3s. Therefore, the side length for the hexagon is 3s6=s2. \frac{3s}{6} = \frac s2.

A hexagon can be made of 66 equilateral triangles with side length s2 \dfrac{s}{2} as shown above. Each triangle is the original triangle scaled down by 12,\dfrac{1}{2}, so the area is scaled down by (12)2=14. (\dfrac{1}{2})^2 = \dfrac{1}{4} . Therefore, the area of each of these triangles is 414=1.4 \cdot \dfrac{1}{4} = 1. Since there are 66 of them, the area is 61=6.6\cdot 1 = 6.

Thus, the answer is C .

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