2017 AMC 8 Problem 23

Below is the video solution and professionally curated solution for Problem 23 of the 2017 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 8 solutions, or check the answer key.

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Concepts:factorarithmetic sequence

Difficulty rating: 1610

23.

Each day for four days, Linda traveled for one hour at a speed that resulted in her traveling one mile in an integer number of minutes. Each day after the first, her speed decreased so that the number of minutes to travel one mile increased by 55 minutes over the preceding day. Each of the four days, her distance traveled was also an integer number of miles. What was the total number of miles for the four trips?

10 10

15 15

25 25

50 50

82 82

Video solution:
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Written solution:

Linda traveled for 6060 minutes every day. Since one mile was traveled in an integer amount of minutes each day, her minutes per mile every day must be a factor of 60.60. The factors of 6060 are 1,2,3,4,5,6,10,12,15,20,30,1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60.60. The only sequence of four of these numbers that differ by 55 are 5,10,15,5, 10, 15, and 20.20. For the four days, she traveled 605+6010+6015+6020=25\dfrac{60}{5} + \dfrac{60}{10} + \dfrac{60}{15} + \dfrac{60}{20} = 25 miles.

Thus, C is the correct answer.

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