1994 AMC 8 第 14 题

先试着解答 1994 AMC 8 第 14 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1994 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

pairball 每次可以由两个孩子玩。9090 分钟内始终只有两个孩子同时在玩,五个孩子轮流上场,使每个人玩的时间相同。每个孩子玩了多少分钟?
Two children at a time can play pairball. For 9090 minutes, with only two children playing at one time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is
99
1010
1818
2020
3636
答案:E
知识点:速率
小提示:
两个孩子玩满 9090 分钟,所以总游戏时间是 2×902 \times 90 个“孩子分钟”
With two children playing for the whole 9090 minutes, the total playing time is 2×902 \times 90 child-minutes
大提示:
把总游戏时间平均分给 55 个孩子
Divide the total playing time equally among the 55 children
解答:
任意时刻都有两个孩子在玩,共 9090 分钟,所以总游戏时间是 2×90=1802 \times 90 = 180 个孩子分钟。
平均分给 55 个孩子,每个孩子玩 1805=36\dfrac{180}{5} = 36 分钟。
所以正确答案是 E。
Two children play at every moment for 9090 minutes, so the total playing time is 2×90=1802 \times 90 = 180 child-minutes.
Split equally among 55 children, each plays 1805=36\dfrac{180}{5} = 36 minutes.
Thus, the correct answer is E .
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