2025 AMC 8 Problem 25

Attempt Problem 25 of the 2025 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

Makayla finds all the possible ways to draw a path in a 5×55 \times 5 diamond-shaped grid. Each path starts at the bottom of the grid and ends at the top, always moving one unit northeast or northwest. She computes the area of the region between each path and the right side of the grid. Two examples are shown in the figures below. What is the sum of the areas determined by all possible paths?
25202520
31503150
38403840
47304730
50505050
Answer: B
Concepts:lattice pathssymmetrycombinations
Small hint:
Pair every path with its mirror image
Big hint:
For a path and its mirror, the two regions fill the whole diamond
Video solution:
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Written solution:
Let XX be the answer.
By symmetry, if the question asked for the sum of areas between each path and the left side of the grid, then the answer would be exactly the same X.X.
But if that answer is added to the original answer, that is exactly the same as the sum over all paths, of the sum of areas to the left and to the right.
For each path, that sum of areas is exactly 25.25.
The number of paths is equal to the number of ways to rearrange LLLLLRRRRR,LLLLLRRRRR, where LL stands for left and RR stands for right, as the path walks up. The number of rearrangements is 1010 choose 5,5, denoted (105).\binom{10}{5}.
So, 2X=25×(105).2X = 25 \times \binom{10}{5}. Dividing by 2,2, we get that XX equals 10×9×8×7×65×4×3×2×1×252, \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1} \times \frac{25}{2}, which is 3150,3150, or choice B.
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