2019 AMC 8 Problem 25

Below is the video solution and professionally curated solution for Problem 25 of the 2019 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

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Concepts:stars and bars

Difficulty rating: 1370

25.

Alice has 2424 apples. In how many ways can she share them with Becky and Chris so that each of the three people has at least two apples?

105105

114114

190190

210210

380380

Video solution:
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Written solution:

Let us assign everybody 22 apples. This leaves us with 2432=1824 - 3 \cdot 2 = 18 apples.

Then, we want to solve a+b+c=18, a + b + c = 18, where a,b,ca, b, c are the additional apples given to Alice, Becky, and Chris.

Note that these are all nonnegative, since we already satisfied the only condition we needed to.

We can use stars and bars to get the number of solutions as (18+3131)=(202)=190. \binom{18 + 3 - 1}{3 - 1} = \binom{20}{2} = 190.

Thus, the correct answer is C.

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