2014 AMC 8 Problem 25

Below is the professionally curated solution for Problem 25 of the 2014 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 8 solutions, or check the answer key.

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Concepts:arcunit conversiondistance rate and time

Difficulty rating: 1460

25.

A straight one-mile stretch of highway, 4040 feet wide, is closed. Robert rides his bike on a path composed of semicircles as shown. If he rides at 55 miles per hour, how many hours will it take to cover the one-mile stretch?

Note: 1 mile = 5280 feet

π11 \dfrac{\pi}{11}

π10 \dfrac{\pi}{10}

π5 \dfrac{\pi}{5}

2π5 \dfrac{2\pi}{5}

2π3 \dfrac{2\pi}{3}

Solution:

Each semicircle advances Robert 4040 feet along the highway, so a one-mile stretch requires 5280/40=1325280/40=132 semicircles.

Each semicircle has diameter 4040 feet, so its arc length is 20π20\pi feet. The total distance Robert rides is 13220π=2640π132\cdot20\pi=2640\pi feet, which is 2640π5280=π2\dfrac{2640\pi}{5280}=\dfrac{\pi}{2} miles.

At 55 miles per hour, the time is π2÷5=π10\dfrac{\pi}{2}\div5=\dfrac{\pi}{10} hours.

Thus, B is the correct answer.

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