2013 AMC 8 Problem 25

Attempt Problem 25 of the 2013 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

A ball with diameter 44 inches starts at point AA to roll along the track shown. The track is comprised of 33 semicircular arcs whose radii are R1=100R_1 = 100 inches, R2=60R_2 = 60 inches, and R3=80R_3 = 80 inches, respectively. The ball always remains in contact with the track and does not slip. What is the distance in inches the center of the ball travels over the course from AA to BB?
238π238 \pi
240π240 \pi
260π260 \pi
280π280 \pi
500π500 \pi
Answer: A
Concepts:arccircumference
Small hint:
The ball center follows offset semicircular arcs.
Big hint:
Subtract the ball radius from outside arcs and add it to the inside arc.
Video solution:
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Written solution:
The ball has radius 22. As the ball rolls, its center follows semicircular arcs parallel to the track. On the first and third arcs the center path is inside the track arcs, so those radii are 100−2=98100-2=98 and 80−2=7880-2=78. On the middle arc the center path is outside the track arc, so that radius is 60+2=6260+2=62.
The total distance traveled by the center is the sum of the three semicircle lengths: (98+62+78)π=238π.(98+62+78)\pi=238\pi.
Thus, A is the correct answer.
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