2006 AMC 8 Problem 7

Attempt Problem 7 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

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7.

Circle XX has a radius of π.\pi. Circle YY has a circumference of 8π.8 \pi. Circle ZZ has an area of 9π.9 \pi. List the circles in order from smallest to largest radius.

X,Y,ZX, Y, Z

Z,X,YZ, X, Y

Y,X,ZY, X, Z

Z,Y,XZ, Y, X

X,Z,YX, Z, Y

Answer: B
Concepts:circlecircumferencecircle area
Difficulty rating: 960
Solution:

Recall that C=2πrC = 2 \pi r and A=πr2.A = \pi r^2. Using these formulas we get that the radius of YY is 8π÷(2π)=4. 8 \pi \div (2 \pi) = 4. We also get that the radius of ZZ is 9π÷π=3. \sqrt{9 \pi \div \pi} = 3. As π\pi is greater than 33 and less than 4,4, the correct order is Z,X,Y.Z,X,Y.

Thus, the answer is B .

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