2006 AMC 8 Problem 22

Attempt Problem 22 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

Three different one-digit positive integers are placed in the bottom row of cells. Numbers in adjacent cells are added and the sum is placed in the cell above them. In the second row, continue the same process to obtain a number in the top cell. What is the difference between the largest and smallest numbers possible in the top cell?
1616
2424
2525
2626
3535
Answer: D
Concepts:optimization
Small hint:
Write the three bottom entries as a,a, b,b, and cc.
Big hint:
The middle bottom entry is counted twice in the top number.
Solution:
If the lower cells contain a,a, b,b, and c,c, the middle row will have a+ba+b and b+cb+c.
This means that the top row will have a+2b+ca+2b+c. To minimize this, put b=1b=1 in the middle and 22 and 33 in the outer cells. This yields a top number of 77.
To maximize it, put b=9b=9 in the middle and 77 and 88 in the outer cells. This yields a top number of 3333. The desired difference is 33−7=2633-7=26.
Thus, D is the correct answer.
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