1992 AMC 8 Problem 22

Below is the professionally curated solution for Problem 22 of the 1992 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 8 solutions, or check the answer key.

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Concepts:perimetercasework

Difficulty rating: 1170

22.

Eight 1×11 \times 1 square tiles are arranged so their outside edges form a polygon with a perimeter of 1414 units. Two additional tiles of the same size are added to the figure so that at least one side of each added tile is shared with a side of one of the original squares. Which of the following could be the perimeter of the new figure?

1515

1717

1818

1919

2020

Solution:

A tile that shares exactly one side adds 22 to the perimeter (four new edges minus two hidden), while a tile sharing two sides adds 0.0.

With two added tiles the perimeter can change by 0,0, 2,2, or 4,4, giving new perimeters of 14,14, 16,16, or 18.18. Of the choices, only 1818 is possible.

Thus, the correct answer is C .

Problem 22 in Other Years

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