2006 AMC 8 Problem 19

Attempt Problem 19 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

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19.

Triangle ABCABC is an isosceles triangle with AB=BC.\overline{AB}=\overline{BC}. Point DD is the midpoint of both BC\overline{BC} and AE,\overline{AE}, and CE\overline{CE} is 1111 units long. Triangle ABDABD is congruent to triangle ECD.ECD. What is the length of BD?\overline{BD}?

44

4.54.5

55

5.55.5

66

Answer: D
Concepts:congruence (geometry)isosceles trianglemidpoint
Difficulty rating: 1410
Solution:

By the congruency condition, we know that AB=EC=11.AB = EC = 11.

Also from the isosceles condition, we know that BC=AB=11.BC = AB = 11.

Since DD is the midpoint of BC,\overline{BC}, we know that BD=BC÷2=5.5BD = BC \div 2 = 5.5

Thus, D is the correct answer.

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