2016 AMC 8 Problem 19

Attempt Problem 19 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

The sum of 2525 consecutive even integers is 10,000.10{,}000. What is the largest of these 2525 consecutive even integers?

360 360

388 388

412 412

416 416

424 424

Answer: E
Concepts:arithmetic sequence
Difficulty rating: 1100
Small Hint:

For an odd number of consecutive terms, the average is the middle term.

Big Hint:

There are 1212 even integers larger than the middle term.

Video solution:
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Written solution:

The average of these numbers is 10,00025=400.\frac{10{,}000}{25} = 400. The largest number is 1212 even numbers away, which means that it equals 400+122=424.400 + 12 \cdot 2 = 424.

Thus, E is the correct answer.

Problem 18#18
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