2012 AMC 8 Problem 19
Below is the video solution and professionally curated solution for Problem 19 of the 2012 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.
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Difficulty rating: 1370
19.
In a jar of red, green, and blue marbles, all but 6 are red marbles, all but 8 are green, and all but 4 are blue. How many marbles are in the jar?
Video solution:
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Written solution:
Let be the number of red marbles, green marbles, and blue marbles respectively. We then know by the statements given. Adding these equations yields This would mean so Therefore, the sum of all of the marbles is
Thus, the answer is C .
Problem 19 in Other Years
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