2006 AMC 8 Problem 15

Below is the professionally curated solution for Problem 15 of the 2006 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

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Concepts:ratelinear equation

Difficulty rating: 1380

15.

Chandra and Bob, who each have a copy of the book, decide that they can save time by "team reading" the novel. In this scheme, Chandra will read from page 11 to a certain page and Bob will read from the next page through page 760,760, finishing the book. When they are through they will tell each other about the part they read. What is the last page that Chandra should read so that she and Bob spend the same amount of time reading the novel?

425425

444444

456456

484484

506506

Solution:

Let xx be the number of pages that Chandra will read. Then Bob will read 760x760 - x pages.

For them to read for the same amount of time, 30x=45(760x)30x=4576045x75x=457605x=3760x=3152x=456. \begin{align*} 30x &= 45(760 - x) \\ 30x &= 45 \cdot 760 - 45x \\ 75x &= 45 \cdot 760 \\ 5x &= 3 \cdot 760 \\ x &= 3 \cdot 152 \\ x &= 456. \end{align*}

Thus, C is the correct answer.

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