1988 AMC 8 Problem 15 — Solution | LIVE by Po-Shen Loh

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1988 AMC 8 Problem 15

Attempt Problem 15 of the 1988 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 8 solutions, or check the answer key.

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15.

What is the reciprocal of $\left(\dfrac{1}{2} + \dfrac{1}{3}\right)?$

$\dfrac{1}{6}$

$\dfrac{2}{5}$

$\dfrac{6}{5}$

$\dfrac{5}{2}$

$5$

Answer: C

Concepts:fraction

Difficulty rating: 660

Solution:

Adding, $\dfrac{1}{2} + \dfrac{1}{3} = \dfrac{3}{6} + \dfrac{2}{6} = \dfrac{5}{6}.$

The reciprocal of $\dfrac{5}{6}$ is $\dfrac{6}{5}.$

Thus, the correct answer is C .

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