1996 AMC 8 Problem 15

Attempt Problem 15 of the 1996 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 8 solutions, or check the answer key.

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15.

The remainder when the product 1492⋅1776⋅1812⋅19961492 \cdot 1776 \cdot 1812 \cdot 1996 is divided by 55 is

00

11

22

33

44

Answer: E
Concepts:units digitmodular arithmetic
Difficulty rating: 930
Small Hint:

The remainder upon division by 55 depends only on the units digit of the product

Big Hint:

Multiply the units digits 2,2, 6,6, 2,2, and 66 and look at that product’s units digit

Solution:

The units digit of the product equals the units digit of 2⋅6⋅2⋅6=144,2 \cdot 6 \cdot 2 \cdot 6 = 144, which is 4.4.

A number ending in 4,4, when divided by 5,5, leaves remainder 4.4.

Thus, the correct answer is E .

Problem 14#14
Full Exam

Problem 15 in Other Years

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