2005 AMC 8 Problem 24

Attempt Problem 24 of the 2005 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 8 solutions, or check the answer key.

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24.

A certain calculator has only two keys [+1+1] and [×2\times 2]. When you press one of the keys, the calculator automatically displays the result. For instance, if the calculator originally displayed "99" and you pressed [+1+1], it would display "10.10." If you then pressed [×2\times 2], it would display "20.20." Starting with the display "1,1," what is the fewest number of keystrokes you would need to reach "200200"?

88

99

1010

1111

1212

Answer: B
Concepts:work backwardsoptimization
Difficulty rating: 1610
Solution:

Work backward from 200200. When the number is even, undo ×2\times2 by dividing by 22; when it is odd, undo +1+1 by subtracting 11.

200,100,50,25,24,12,6,3,2,1200,100,50,25,24,12,6,3,2,1 uses 99 reverse steps, so 99 keystrokes are enough.

Eight keystrokes are not enough: the largest value below 200200 reachable in 88 keystrokes is obtained by ×2,+1\times2,+1 followed by six doublings, giving 326=1923\cdot2^6=192. The next larger possibilities overshoot to at least 256256, so 200200 cannot be reached in 88 keystrokes.

Thus, B is the correct answer.

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