2004 AMC 8 Problem 24

Attempt Problem 24 of the 2004 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.

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24.

In the figure, ABCDABCD is a rectangle and EFGHEFGH is a parallelogram. Using the measurements given in the figure, what is the length dd of the segment that is perpendicular to HE\overline{HE} and FG?\overline{FG}?

6.86.8

7.17.1

7.67.6

7.87.8

8.18.1

Answer: C
Concepts:parallelogramarea decompositionPythagorean Theorem
Difficulty rating: 1540
Small Hint:

Find the area of the rectangle and subtract the four corner triangles.

Big Hint:

Use the Pythagorean theorem to get the parallelogram base HE.HE.

Solution:

The rectangle has side lengths 1010 and 8,8, so its area is 80.80.

The four corner triangles have total area 21234+21265=12+30=42. \begin{aligned} &2\cdot\frac12\cdot3\cdot4 \\ &\quad{}+2\cdot\frac12\cdot6\cdot5 \\ &=12+30=42. \end{aligned} Thus parallelogram EFGHEFGH has area 8042=38.80-42=38.

Segment HEHE has length 55 by the 3453-4-5 right triangle. Since the parallelogram area is HEd,HE\cdot d, we have 5d=38,5d=38, so d=7.6.d=7.6.

Thus, C is the correct answer.

Problem 23#23
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