2004 AMC 8 Problem 2
Attempt Problem 2 of the 2004 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
2.
How many different four-digit numbers can be formed by rearranging the four digits in
Answer: B
Small hint:
A four-digit number cannot start with
Big hint:
Choose which nonzero digit comes first, then place the other nonzero digit.
Solution:
Note that there are non-zero digits that could be the thousands digit.
After choosing that, we need to arrange the other digits. There are spots for the other non-zero digit.
This gives us possible numbers.
Thus, B is the correct answer.
Problem 2 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1996 AMC 8
- 1997 AMC 8
- 1998 AMC 8
- 1999 AMC 8
- 2000 AMC 8
- 2001 AMC 8
- 2002 AMC 8
- 2003 AMC 8
- 2005 AMC 8
- 2006 AMC 8
- 2007 AMC 8
- 2008 AMC 8
- 2009 AMC 8
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