2004 AMC 8 Problem 2
Attempt Problem 2 of the 2004 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
2.
How many different four-digit numbers can be formed by rearranging the four digits in ?
Answer: B
Solution:
Note that there are non-zero digits that could be the thousands digit.
After choosing that, we need to arrange the other digits. There are spots for the other non-zero digit.
This gives us possible numbers.
Thus, B is the correct answer.
Problem 2 in Other Years
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