2002 AMC 8 Problem 2

Attempt Problem 2 of the 2002 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

How many different combinations of $5\$5 bills and $2\$2 bills can be used to make a total of $17\$17? Order does not matter in this problem.

22

33

44

55

66

Answer: A
Concepts:Diophantine Equationparitycasework
Difficulty rating: 610
Solution:

Since the total $17\$17 is odd, the number of $5\$5 bills must be odd.

One $5\$5 bill leaves $12\$12, which is six $2\$2 bills. Three $5\$5 bills leave $2\$2, which is one $2\$2 bill. Five $5\$5 bills is too much.

Therefore, there are 22 combinations.

Thus, A is the correct answer.

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