2002 AMC 8 Problem 25

Attempt Problem 25 of the 2002 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

Loki, Moe, Nick and Ott are good friends. Ott had no money, but the others did. Moe gave Ott one-fifth of his money, Loki gave Ott one-fourth of his money and Nick gave Ott one-third of his money. Each gave Ott the same amount of money. What fractional part of the group’s money does Ott now have?
110\dfrac{1}{10}
14\dfrac{1}{4}
13\dfrac{1}{3}
25\dfrac{2}{5}
12\dfrac{1}{2}
Answer: B
Concepts:fractionwork backwards
Small hint:
Assume each friend gives Ott the same convenient amount.
Big hint:
If each gives Ott $1,\$1, work backward to each friend’s original amount.
Solution:
Because only the fractions matter, suppose each person gave Ott $1.\$1. This means that Moe had $5,\$5, Loki had $4,\$4, and Nick had $3\$3 originally.
The transfers do not change the group’s total amount of money, which is $5+$4+$3=$12. \$5 + \$4 + \$3 = \$12. Ott now has $3.\$3.
This means that Ott has 312=14 \dfrac{3}{12} = \dfrac{1}{4} of the group’s money.
Thus, B is the correct answer.
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