2002 AMC 8 Problem 21
Attempt Problem 21 of the 2002 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
21.
Harold tosses a nickel four times. The probability that he gets at least as many heads as tails is
Answer: E
Small hint:
At least as many heads as tails means or heads.
Big hint:
Count outcomes by choosing which tosses are heads.
Solution:
There are equally likely outcomes for four coin tosses.
At least as many heads as tails means getting or heads. The number of such outcomes is
Thus the probability is
Thus, E is the correct answer.
Problem 21 in other years
- 1985 AMC 8
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