1987 AMC 8 Problem 21

Attempt Problem 21 of the 1987 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1987 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

Suppose nn^\ast means 1n,\dfrac1n, the reciprocal of n.n. For example, 5=15.5^\ast = \dfrac15. How many of the following four statements are true?

(i) 3+6=93^\ast + 6^\ast = 9^\ast; (ii) 64=26^\ast - 4^\ast = 2^\ast; (iii) 26=122^\ast \cdot 6^\ast = 12^\ast; (iv) 10÷2=510^\ast \div 2^\ast = 5^\ast

00

11

22

33

44

Answer: C
Concepts:custom operationfraction

Difficulty rating: 1030

Solution:

(i) 13+16=12,\dfrac13 + \dfrac16 = \dfrac12, but 9=19,9^\ast = \dfrac19, so false. (ii) 1614=112,\dfrac16 - \dfrac14 = -\dfrac{1}{12}, but 2=12,2^\ast = \dfrac12, so false.

(iii) 1216=112=12,\dfrac12 \cdot \dfrac16 = \dfrac{1}{12} = 12^\ast, true. (iv) 110÷12=15=5,\dfrac{1}{10} \div \dfrac12 = \dfrac15 = 5^\ast, true.

So exactly 22 of the statements are true.

Thus, the correct answer is C .

← Problem 20#20Full ExamProblem 22#22 →

Problem 21 in Other Years

1985 AMC 8 · 1986 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8