1987 AMC 8 Problem 21

Attempt Problem 21 of the 1987 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1987 AMC 8 solutions, or check the answer key.

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21.

Suppose n∗n^\ast means 1n,\dfrac1n, the reciprocal of n.n. For example, 5∗=15.5^\ast = \dfrac15. How many of the following four statements are true?

(i)3∗+6∗=9∗\mathrm{(i)}\quad 3^\ast + 6^\ast = 9^\ast

(ii)6∗−4∗=2∗\mathrm{(ii)}\quad 6^\ast - 4^\ast = 2^\ast

(iii)2∗⋅6∗=12∗\mathrm{(iii)}\quad 2^\ast \cdot 6^\ast = 12^\ast

(iv)10∗÷2∗=5∗\mathrm{(iv)}\quad 10^\ast \div 2^\ast = 5^\ast

00

11

22

33

44

Answer: C
Concepts:custom operationfraction
Difficulty rating: 1030
Small Hint:

Replace each n∗n^\ast with 1n\dfrac1n and test the two sides of each statement

Big Hint:

For (iv),\mathrm{(iv)}, 10∗÷2∗=110÷12=110⋅210^\ast \div 2^\ast = \dfrac{1}{10} \div \dfrac12 = \dfrac{1}{10} \cdot 2

Solution:

(i)\mathrm{(i)} 13+16=12,\dfrac13 + \dfrac16 = \dfrac12, but 9∗=19,9^\ast = \dfrac19, so false. (ii)\mathrm{(ii)} 16−14=−112,\dfrac16 - \dfrac14 = -\dfrac{1}{12}, but 2∗=12,2^\ast = \dfrac12, so false.

(iii)\mathrm{(iii)} 12⋅16=112=12∗,\dfrac12 \cdot \dfrac16 = \dfrac{1}{12} = 12^\ast, true. (iv)\mathrm{(iv)} 110÷12=15=5∗,\dfrac{1}{10} \div \dfrac12 = \dfrac15 = 5^\ast, true.

So exactly 22 of the statements are true.

Thus, the correct answer is C .

Problem 20#20
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