1993 AMC 8 Problem 15

Attempt Problem 15 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

The arithmetic mean (average) of four numbers is 85.85. If the largest of these numbers is 97,97, then the mean of the remaining three numbers is
81.081.0
82.782.7
83.083.0
84.084.0
84.384.3
Answer: A
Concepts:mean
Small hint:
The four numbers sum to 4×854 \times 85
Big hint:
Subtract the largest number, then divide the remaining sum by 33
Solution:
The four numbers sum to 4×85=340,4 \times 85 = 340, so the remaining three sum to 340−97=243.340 - 97 = 243.
Their mean is 243÷3=81.243 \div 3 = 81.
Thus, the correct answer is A .
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