1993 AMC 8 Problem 16

Below is the professionally curated solution for Problem 16 of the 1993 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:continued fractionfraction

Difficulty rating: 860

16.

What is the value of the following expression?

11+12+13\cfrac{1}{1 + \cfrac{1}{2 + \cfrac{1}{3}}}

16\dfrac16

310\dfrac{3}{10}

710\dfrac{7}{10}

56\dfrac56

103\dfrac{10}{3}

Solution:

Starting inside, 2+13=73,2 + \dfrac13 = \dfrac73, so 17/3=37.\dfrac{1}{7/3} = \dfrac37.

Then 1+37=107,1 + \dfrac37 = \dfrac{10}{7}, and the whole expression is 110/7=710.\dfrac{1}{10/7} = \dfrac{7}{10}.

Thus, the correct answer is C .

← Problem 15#15Full ExamProblem 17#17 →

Problem 16 in Other Years

1985 AMC 8 · 1986 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8