1990 AMC 8 Problem 16

Attempt Problem 16 of the 1990 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.

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16.

What is the value of the following expression?

19901980+19701960+20+10 \begin{aligned} &1990 - 1980 + 1970 - 1960 \\ &\quad {}+ \cdots - 20 + 10 \end{aligned}

990-990

10-10

990990

10001000

19901990

Answer: D
Concepts:pairing and grouping

Difficulty rating: 1060

Solution:

Group the terms as (19901980)(1990 - 1980) +(19701960)+ (1970 - 1960) ++ \cdots +(3020)+ (30 - 20) +10.+ 10. Each parenthesized pair equals 1010.

The first elements 1990,1970,,301990, 1970, \ldots, 30 number 9999, so there are 9999 pairs, giving 990990, plus the leftover +10+10 at the end for a total of 10001000.

Thus, the correct answer is D .

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