2025 AMC 12B Problem 9

Attempt Problem 9 of the 2025 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

What is the tens digit of 666?6^{6^6}?
11
33
55
77
99
Answer: C
Concepts:modular exponentiationdigits
Small hint:
The tens digit is determined by 666 mod 1006^{6^6} \bmod 100
Big hint:
For n≥2,n \ge 2, 6n mod 1006^n \bmod 100 cycles with period 5;5; reduce the exponent 666^6 modulo 55
Solution:
Here 66=46656.6^6 = 46656. For n≥2,n \ge 2, the last two digits of 6n6^n cycle with period 55 through 36,16,96,76,56.36, 16, 96, 76, 56. Since 46656≡1(mod5),46656 \equiv 1 \pmod 5, 6466566^{46656} ends in 56,56, so the tens digit is 5.5.
Thus, the correct answer is C.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.