2001 AMC 12 Problem 9

Below is the professionally curated solution for Problem 9 of the 2001 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 12 solutions, or check the answer key.

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Concepts:functional equationsubstitution

Difficulty rating: 1440

9.

Let ff be a function satisfying f(xy)=f(x)yf(xy) = \dfrac{f(x)}{y} for all positive real numbers xx and y.y. If f(500)=3,f(500) = 3, what is the value of f(600)?f(600)?

11

22

52\dfrac{5}{2}

33

185\dfrac{18}{5}

Solution:

Choose x=500x = 500 and y=65y = \dfrac{6}{5} so that xy=600.xy = 600. Then f(600)=f(500)6/5=36/5=52. f(600) = \dfrac{f(500)}{6/5} = \dfrac{3}{6/5} = \dfrac{5}{2}.

Thus, the correct answer is C.

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