2022 AMC 12B Problem 1 — Solution | LIVE by Po-Shen Loh

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2022 AMC 12B Problem 1

Attempt Problem 1 of the 2022 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Define $x \diamond y$ to be $|x - y|$ for all real numbers $x$ and $y.$ What is the value of

$(1 \diamond (2 \diamond 3)) - ((1 \diamond 2) \diamond 3)?$

$-2$

$-1$

$0$

$1$

$2$

Answer: A

Concepts:custom operation absolute value order of operations

Difficulty rating: 890

Solution:

Since $2 \diamond 3 = |2-3| = 1,$ we get $1 \diamond (2 \diamond 3) = 1 \diamond 1 = 0.$

Since $1 \diamond 2 = |1-2| = 1,$ we get $(1 \diamond 2) \diamond 3 = 1 \diamond 3 = |1-3| = 2.$

The value is $0 - 2 = -2.$

Thus, the correct answer is A.

Problem 2#2 →

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