2022 AMC 12A Problem 11

Attempt Problem 11 of the 2022 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

What is the product of all real numbers xx such that the distance on the number line between log⁡6x\log_6 x and log⁡69\log_6 9 is twice the distance on the number line between log⁡610\log_6 10 and 1?1?
1010
1818
2525
3636
8181
Answer: E
Concepts:logarithmabsolute value
Small hint:
log⁡610−1=log⁡6106=log⁡653\log_6 10-1=\log_6\dfrac{10}{6}=\log_6\dfrac53
Big hint:
The condition is ∣log⁡6x9∣=log⁡6259\left|\log_6\dfrac{x}{9}\right|=\log_6\dfrac{25}{9}
Solution:
The right-hand distance is ∣log⁡610−1∣=log⁡653,|\log_6 10-1|=\log_6\dfrac53, so twice it is 2log⁡653=log⁡6259.2\log_6\dfrac53=\log_6\dfrac{25}{9}.
Thus ∣log⁡6x9∣=log⁡6259,\left|\log_6\dfrac{x}{9}\right|=\log_6\dfrac{25}{9}, giving x9=259\dfrac{x}{9}=\dfrac{25}{9} or x9=925,\dfrac{x}{9}=\dfrac{9}{25}, so x=25x=25 or x=8125.x=\dfrac{81}{25}.
Their product is 25⋅8125=81.25\cdot\dfrac{81}{25}=81.
Thus, the correct answer is E.
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