2015 AMC 12B Problem 11

Attempt Problem 11 of the 2015 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 12B solutions, or check the answer key.

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11.

The line 12x+5y=6012x + 5y = 60 forms a triangle with the coordinate axes. What is the sum of the lengths of the altitudes of this triangle?

2020

36017\dfrac{360}{17}

1075\dfrac{107}{5}

432\dfrac{43}{2}

28113\dfrac{281}{13}

Answer: E
Concepts:coordinate geometryright trianglealtitude
Difficulty rating: 1510
Solution:

The line meets the axes at (5,0)(5, 0) and (0,12),(0, 12), so the triangle is right with legs 55 and 1212 and hypotenuse 13.13. Its area is 30.30.

Two altitudes are the legs 55 and 12;12; the altitude to the hypotenuse is 23013=6013.\dfrac{2 \cdot 30}{13} = \dfrac{60}{13}. The sum is 17+6013=28113.17 + \dfrac{60}{13} = \dfrac{281}{13}.

Thus, the correct answer is E.

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