2014 AMC 12B Problem 1

Attempt Problem 1 of the 2014 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Leah has 1313 coins, all of which are pennies and nickels. If she had one more nickel than she has now, then she would have the same number of pennies and nickels. In cents, how much are Leah’s coins worth?
3333
3535
3737
3939
4141
Answer: C
Concepts:linear equationmoney
Small hint:
Let nn be the number of nickels, so there are 13−n13-n pennies
Big hint:
Adding one nickel gives n+1n+1 nickels, which must equal the 13−n13-n pennies
Solution:
Let nn be the number of nickels, so Leah has 13−n13-n pennies. One more nickel would give her n+1n+1 nickels, and this equals the number of pennies: n+1=13−n. n+1 = 13-n. Solving gives n=6,n=6, so there are 66 nickels and 77 pennies.
The total value is 6⋅5+7=376\cdot5 + 7 = 37 cents.
Thus, the correct answer is C.
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